(2x^2+3x-5)(x^2-16)=0

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Solution for (2x^2+3x-5)(x^2-16)=0 equation: 


Simplifying
(2x2 + 3x + -5)(x2 + -16) = 0

Reorder the terms:
(-5 + 3x + 2x2)(x2 + -16) = 0

Reorder the terms:
(-5 + 3x + 2x2)(-16 + x2) = 0

Multiply (-5 + 3x + 2x2) * (-16 + x2)
(-5(-16 + x2) + 3x * (-16 + x2) + 2x2 * (-16 + x2)) = 0
((-16 * -5 + x2 * -5) + 3x * (-16 + x2) + 2x2 * (-16 + x2)) = 0
((80 + -5x2) + 3x * (-16 + x2) + 2x2 * (-16 + x2)) = 0
(80 + -5x2 + (-16 * 3x + x2 * 3x) + 2x2 * (-16 + x2)) = 0
(80 + -5x2 + (-48x + 3x3) + 2x2 * (-16 + x2)) = 0
(80 + -5x2 + -48x + 3x3 + (-16 * 2x2 + x2 * 2x2)) = 0
(80 + -5x2 + -48x + 3x3 + (-32x2 + 2x4)) = 0

Reorder the terms:
(80 + -48x + -5x2 + -32x2 + 3x3 + 2x4) = 0

Combine like terms: -5x2 + -32x2 = -37x2
(80 + -48x + -37x2 + 3x3 + 2x4) = 0

Solving
80 + -48x + -37x2 + 3x3 + 2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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